Anyone guess the bug in the squareRootBi code?
Not sure if this is what he was referring to: There's no solution for the square root of a negative number in the set of real numbers, but the function doesn't insure that x is positive.
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Not sure if this is what he was referring to: There's no solution for the square root of a negative number in the set of real numbers, but the function doesn't insure that x is positive.